(3y^2-8y+1)-(2y^2-8y+8)=

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Solution for (3y^2-8y+1)-(2y^2-8y+8)= equation: 


Simplifying
(3y2 + -8y + 1) + -1(2y2 + -8y + 8) = 0

Reorder the terms:
(1 + -8y + 3y2) + -1(2y2 + -8y + 8) = 0

Remove parenthesis around (1 + -8y + 3y2)
1 + -8y + 3y2 + -1(2y2 + -8y + 8) = 0

Reorder the terms:
1 + -8y + 3y2 + -1(8 + -8y + 2y2) = 0
1 + -8y + 3y2 + (8 * -1 + -8y * -1 + 2y2 * -1) = 0
1 + -8y + 3y2 + (-8 + 8y + -2y2) = 0

Reorder the terms:
1 + -8 + -8y + 8y + 3y2 + -2y2 = 0

Combine like terms: 1 + -8 = -7
-7 + -8y + 8y + 3y2 + -2y2 = 0

Combine like terms: -8y + 8y = 0
-7 + 0 + 3y2 + -2y2 = 0
-7 + 3y2 + -2y2 = 0

Combine like terms: 3y2 + -2y2 = 1y2
-7 + 1y2 = 0

Solving
-7 + 1y2 = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '7' to each side of the equation.
-7 + 7 + 1y2 = 0 + 7

Combine like terms: -7 + 7 = 0
0 + 1y2 = 0 + 7
1y2 = 0 + 7

Combine like terms: 0 + 7 = 7
1y2 = 7

Divide each side by '1'.
y2 = 7

Simplifying
y2 = 7

Take the square root of each side:
y = {-2.645751311, 2.645751311}

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